The solution of differential edquation `(dy)/(dx) +1 = cosec (x+y)` isA. `cos(x+y)+x=C`B. `cos(x+y)=C`C. `sin(x+y)+x=C`D. `sin(x+y)+sin(x+y)=C`

The solution of differential edquation `(dy)/(dx) +1 = cosec (x+y)` is

1.	The solution of differential edquation `(dy)/(dx) +1 = cosec (x+y)` isA. `cos(x+y)+x=C`B. `cos(x+y)=C`C. `sin(x+y)+x=C`D. `sin(x+y)+sin(x+y)=C`
Answer» Correct Answer - b Given `(dy)/(dx) +1 = " cosec" (x+y)` Put ` x+y = t` ` rArr 1+ (dy)/(dx) = (dt)/(dx)` ` :. (dt)/("cosec t ") = dx ` ` rArr int sin t dt = int dx ` ` rArr cos ( x+y) +x = C`

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The solution of differential edquation `(dy)/(dx) +1 = cosec (x+y)` isA. `cos(x+y)+x=C`B. `cos(x+y)=C`C. `sin(x+y)+x=C`D. `sin(x+y)+sin(x+y)=C`

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