InterviewSolution
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The solution of `(dy)/(dx)+1 = e^(x+y) ` isA. ` e^(-(x+y))+x+C=0`B. ` e^((-x+y)) - x + C = 0 `C. ` e^(x+y) + x+C = 0`D. ` e^(x+y)- x + C = 0 ` |
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Answer» Correct Answer - a Given, ` (dy)/(dx) +1 = e^(x+y)` `rArr 1 + (dy)/(dx) = (dz)/(dx)` ` :. (dz)/(dx) = e^(z)` On integrating , we get ` rArr int e^(-z) dz = int dx` `rArr - e^(-z) = x+C` ` rArr x + e^(-(x+y)) + C = 0` |
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