InterviewSolution
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The solution of `(dy)/(dx)=(x^2+y^2+1)/(2x y)`satisfying `y(1)=1`is given by(a) a system of parabolas(b) a system of circles(c)`( d ) (e) (f) y^(( g )2( h ))( i )=x(( j ) (k)1+x (l))-1( m )`(n)(d) `( o ) (p) (q) (r)(( s ) (t) x-2( u ))^(( v )2( w ))( x )+( y ) (z)(( a a ) (bb) y-3( c c ))^(( d d )2( e e ))( f f )=5( g g )`(hh)A. a system of parabolasB. a system of circlesC. `y^(2)=x(1+x)-1`D. `(x-2)^(2)+(y-3)^(2)=5` |
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Answer» Correct Answer - C Rewritting the given equation is `2xy(dy)/(dx) -y^(2)=1+x^(2)` or `2y(dy)/(dx)-1/xy^(2)=1/x+x` Putting `y^(2)=u`, we have `(du)/(dx) -1/xu=1/x+x` I.F. `=e^(-int1/xdx)=1/x` Thus, solution is `u1/x=int(1/x^(2)+1)dx=-1/x+x+C` or `y^(2)=(x^(2)-1)+Cx` Since `y(1)=1`, we get C=1. Hence, `y^(2)=x(1+x)-1` which represents a system of hyperbola. |
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