1.

The solution of the differential equation (1+y^2)+(x-e^(tan^-1 y))(dy)/(dx)=0, is

Answer»

`x E^("TAN"^(-1)y)="Tan"^(-1)y+k`
`x e^("2TAN"^(-1)y)=e^("Tan"^(-1)y)+k`
`(x-2)=KE^(-"Tan"^(-1)y)`
`2x " "e^("Tan"^(-1)y)=e^(2"Tan"^(-1)y)+k`

ANSWER :4


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