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The solution of the differential equation `(dy)/(dx) = 1/(x+y^(2))` isA. `y = -x^(2) - 2x - 2 +Ce^(x)`B. `y = x^(2) + 2x +2 - Ce^(x)`C. ` x = -y^(2) - 2y + 2 - Ce^(y)`D. ` x = -y^(2) - 2y - 2 +Ce^(y)` |
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Answer» Correct Answer - d Given differential equation is ` (dy)/(dx) = 1/(x+y^(2))` ` rArr (dx)/(dy)- x = y^(2)` Here, `P = -1 , Q = y^(2)` ` :. IF = e^(int - dy) = e^(-y)` |
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