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The solution of the differential equation `(dy)/(dx) = e^(y+x) +e^(y-x)` isA. ` e^(-y) = e^(x) -e^(-x)+C`B. ` e^(-y) = e^(-x)-e^(x) +C`C. ` e^(-y) = e^(x) +e^(-x)+C`D. ` e^(-y) +e^(x) +e^(-x) =C` |
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Answer» Correct Answer - b Given differential equation is ` (dy)/(dx) = e^(y+x) +e^(y-x)` On integrating both sides , we get ` rArr int e^(-y) dy = int (e^(x)+e^(-x))dx` ` rArr -e^(-y) = e^(x) -e^(-x) -C` ` rArr e^(-y) = e^(-x) -e^(x) +C` |
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