The solution of the differential equation dydx+x(x+y)=x3(x+y)3−1 is – InterviewSolution

1.	The solution of the differential equation dydx+x(x+y)=x3(x+y)3−1 is a(x+y)b=c(x2+1)+kex2, then a+b+c is equal to
Answer» The solution of the differential equation $\frac{d y}{d x} + x (x + y) = x^{3} (x + y)^{3} - 1$ is $\frac{a}{(x + y)^{b}} = c (x^{2} + 1) + k e^{x^{2}},$ then $a + b + c$ is equal to

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