InterviewSolution
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The solution of the equation log `((dy)/(dx))=a x+b y`is(a)`( b ) (c) (d)(( e ) (f) e^(( g ) (h) b y (i))( j ))/( k ) b (l) (m)=( n )(( o ) (p) e^(( q ) (r) a x (s))( t ))/( u ) a (v) (w)+c (x)`(y)(b) `( z ) (aa) (bb)(( c c ) (dd) e^(( e e ) (ff)-b y (gg))( h h ))/( i i )(( j j )-b)( k k ) (ll)=( m m )(( n n ) (oo) e^(( p p ) (qq) a x (rr))( s s ))/( t t ) a (uu) (vv)+c (ww)`(xx)(c)`( d ) (e) (f)(( g ) (h) e^(( i ) (j)-b y (k))( l ))/( m ) a (n) (o)=( p )(( q ) (r) e^(( s ) (t) a x (u))( v ))/( w ) b (x) (y)+c (z)`(aa)(d) None of theseA. `(-e^(-by))/( b ) = ( e ^(ax))/( a ) + C `B. `e^(ax) - e ^(-by) = C `C. ` b e ^(ax ) + a e^(by) = C `D. none of these |
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Answer» Correct Answer - A `(dy)/(dx) = e ^( ax + by ) rArr int e ^(- by ) dy = int e ^(ax) dx rArr (e ^(-by))/( - b ) = (e ^(ax))/( a ) +C`. |
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