The solution of the system of equations 2x + 3y + 5 = 0 and 3x – 2y

1.	The solution of the system of equations 2x + 3y + 5 = 0 and 3x – 2y – 12 = 0 is ………………… A) x = -3, y = 2 B) x = 2, y = -3 C) x = 3, y = -2D) x = -2, y = 3
Answer» Correct option is (B) x = 2, y = -3 Given system of equations is 2x + 3y + 5 = 0 __________(1) and 3x – 2y – 12 = 0 __________(2) Multiply equation (1) by 2 and equation (2) by 3, we get 4x + 6y + 10 = 0 __________(3) 9x - 6y - 36 = 0 __________(4) By adding equations (3) & (4), we get 13x - 26 = 0 \(\Rightarrow x=\frac{26}{13}=2\) Then from (1), we have \(y=\frac{-(2x+5)}3=\frac{-(2\times2+5)}3\) \(=\frac{-9}3=-3\) Hence, the solution of given system of equation is x = 2, y = -3. Correct option is B) x = 2, y = -3

The solution of the system of equations 2x + 3y + 5 = 0 and 3x – 2y – 12 = 0 is ………………… A) x = -3, y = 2 B) x = 2, y = -3 C) x = 3, y = -2D) x = -2, y = 3

Answer»

Correct option is (B) x = 2, y = -3

Given system of equations is

2x + 3y + 5 = 0 __________(1)

and 3x – 2y – 12 = 0 __________(2)

Multiply equation (1) by 2 and equation (2) by 3, we get

4x + 6y + 10 = 0 __________(3)

9x - 6y - 36 = 0 __________(4)

By adding equations (3) & (4), we get

13x - 26 = 0

\(\Rightarrow x=\frac{26}{13}=2\)

Then from (1), we have

\(y=\frac{-(2x+5)}3=\frac{-(2\times2+5)}3\)

\(=\frac{-9}3=-3\)

Hence, the solution of given system of equation is x = 2, y = -3.

Correct option is B) x = 2, y = -3