1.

The solution of x(dy)/(dx) + 2y = x^(2) log x is

Answer»

`YX^(2) = (x^(4))/(4)LOG x - (x^(4))/(16) + c`
`yx^(2) = (x^(4))/(4)log x + (x^(4))/(16) + c`
`XY^(2) = (x^(4))/(4)log x - (x^(4))/(16) + c`
`xy^(2) = (x^(4))/(4)log x - (x^(4))/(6) + c`

Answer :A


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