1.

The solution of y'' = y' tan x = sin x is

Answer»

`y =(1)/(2) (sin x) + ALOG (SEC x + tan x) + b`
`y = -(1)/(2) sin x + a log (sec x = tan x) + b`
`y = sin x + a log (sec x + tan x) + b`
`y = - sin x + a log (sec x + tan x) + b`

Answer :B


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