1.

The SOP , `E^(@)` for the half reactions are `Zn to Zn^(2+) + 2e , E^(@) = + 0.76 V` `Ag to Ag^(+) + e , E^(@) = -0.77 V` `E^(@)` of the cell , `Ag^(+)+ Zn to Zn^(2+) + Ag` is :A. `+ 1.53`B. `-1.53 `C. `-0.01`D. `+0.01`

Answer» Correct Answer - A
`E_("cell")^(@) = E_(OP_(Zn))^(@) + E_(RP_(Ag))^(@) = 0.76 + 0.77 = 1.53` V


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