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The sotubility of AgCI will be minimum in ……(a) 0.00 1 M AgNO3(b) pure water (c) 0.01 M CaCI2(d) 0.01 M NaCl |
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Answer» (c) 0.01 M CaCl2 0.01 M CaCI2 gives maximum CI- ions to keep Ksp of AgCl constant, decrease in [Ag+] will be maximum. |
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