1.

The species having bond order different from that in CO is :

Answer»

`NO^(-)`
`NO^(+)`
`CN^(-)`
`N_(2)`

Solution :`CO : KK(sigma_(2s))^(2)(sigma_(2s)^(**))^(2)(pi_(2p_(X)))^(2)(pi_(2p_(y)))^(2)(sigma_(2p_(z)))^(2)`
`B.O=(8-2)/(2)=3`
`NO^(-):KK(sigma_(2s))^(2)(sigma_(2s)^(**))^(2)(pi_(2p_(x)))^(2)(pi_(2p_(y)))^(2)(sigma_(2p_(z)))^(2)(pi_(2p_(x))^(**))^(1)(pi_(2p_(y))^(**))^(1)`
`B.O.=(8-4)/(2)=2`
`NO^(+):KK(sigma_(2s))^(2)(sigma_(2s)^(**))^(2)(pi_(2p_(x)))^(2)(pi_(2p_(y)))^(2)(sigma_(2p_(z)))^(2)`
`B.O.=(8-2)/(2)=3`
`CN^(-): KK(sigma_(2s))^(2)(sigma_(2s)^(**))^(2)(pi_(2p_(x)))^(2)(pi_(2p_(y)))^(2)(sigma_(2p_(z)))^(2)`
`B.O.=(8-2)/(2)=3` `N_(2):KK(sigma_(2s))^(2)(sigma_(2s)^(**))^(2)(pi_(2p_(x)))^(2)(pi_(2p_(y)))^(2)(sigma_(2p_(z)))^(2)`
`B.O.=(8-2)/(2)=3`
`therefore NO^(-)`has different BOND order.


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