1.

The species in which the N-atom is in a state of sp hybridisation is

Answer»

`NO_(3)^(-)`
`NO_(2)`
`NO_(3)^(+)`
`NO_(2)^(-)`

Solution :Hybridizatio `(H)=(1)/(2)`. [ no. of valenceelectrons of central +no. of Movement atoms attached to it +(-ve charge if any)- (+ve charge if any)]
`NO_(2)^(+)=(1)/(2)[5+0+0-1]=2`i.e., sp hybridisation
`NO_(2)^(-)=(1)/(2)[5+2+1-0]=3` I.e., `ps^(2)` hybridisation
`NO_(3)^(-)=(1)/(2)[5+0+1-0]=3` i.e., `sp^(2)` hybridisation
The LEWIS STRUCTURE of NO, shows a bent molecular GEOMETRY with trigonal planar electron pair geometry Door hence the hybridization will be `sp^(2)`


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