1.

The specific conductance of 0.1N KCl solution at 23^@C is 0.012 Ohm^(-1) cm^(-1) . The resistance of the cell containing the solution at the same temperature was found to be 55 Ohm. The cell constant will be ………. .

Answer»

`0.142 cm^(-1)`
`0.66 cm^(-1)`
`0.918 cm^(-1)`
`1.12 cm^(-1)`

Solution :`K = 1/R xx "CELL constant"`
`:.` Cell constant = `k xx R`
`= 0.012 xx 55`
`= 0.66 cm^(-1)`.


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