The specific conductance of a `0.1 N KCl` solution at `23^(@)C` is `0.012 ohm^(-1) cm^(-1)`. The resistance of cell containing the solution at the same tempreature was found to be `55 ohm`. The cell constant will beA. `0.142cm^(-1)`B. `0.66cm^(-1)`C. `0.918cm^(-1)`D. `1.12cm^(-1)`

The specific conductance of a `0.1 N KCl` solution at `23^(@)C` is `0.

1.	The specific conductance of a `0.1 N KCl` solution at `23^(@)C` is `0.012 ohm^(-1) cm^(-1)`. The resistance of cell containing the solution at the same tempreature was found to be `55 ohm`. The cell constant will beA. `0.142cm^(-1)`B. `0.66cm^(-1)`C. `0.918cm^(-1)`D. `1.12cm^(-1)`
Answer» Correct Answer - B Specific conductance =Conductance xx Cell constant 0.012`ohm^(-1) cm^(-1)=(1)/(55)ohmxx` Cell constant ohm xx Cell constant Cell constant `=53xx0.012cm^(-1)=0.66cm^(-1)`

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The specific conductance of a `0.1 N KCl` solution at `23^(@)C` is `0.012 ohm^(-1) cm^(-1)`. The resistance of cell containing the solution at the same tempreature was found to be `55 ohm`. The cell constant will beA. `0.142cm^(-1)`B. `0.66cm^(-1)`C. `0.918cm^(-1)`D. `1.12cm^(-1)`

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