The specific conductance of a `0.1 N KCl` solution at `23^(@)C` is `0.012 ohm^(-1) cm^(-1)`. The resistance of cell containing the solution at the same tempreature was found to be `55 ohm`. The cell constant will beA. `0.142 cm^(-1)`B. `0.66 cm^(-1)`C. `0.918 cm^(-1)`D. `1.12 cm^(-1)`

The specific conductance of a `0.1 N KCl` solution at `23^(@)C` is `0.

1.	The specific conductance of a `0.1 N KCl` solution at `23^(@)C` is `0.012 ohm^(-1) cm^(-1)`. The resistance of cell containing the solution at the same tempreature was found to be `55 ohm`. The cell constant will beA. `0.142 cm^(-1)`B. `0.66 cm^(-1)`C. `0.918 cm^(-1)`D. `1.12 cm^(-1)`
Answer» Correct Answer - B The specific conductance (or conductivity) of the solution is given by the equation : `kappa = (1)/(c) xx` cell constant Thus, the cell constant `(G^())` is given by the equation: `(G^()) = R kappa` `= (55 "ohm")(0.012 "ohm"^(-1)cm^(-1))` `= 0.66 cm^(-1)`

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The specific conductance of a `0.1 N KCl` solution at `23^(@)C` is `0.012 ohm^(-1) cm^(-1)`. The resistance of cell containing the solution at the same tempreature was found to be `55 ohm`. The cell constant will beA. `0.142 cm^(-1)`B. `0.66 cm^(-1)`C. `0.918 cm^(-1)`D. `1.12 cm^(-1)`

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