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The specific conductance of a N/10 KCl at `25^(@)C` is 0.0112 `ohm^(-1) cm^(-1)`. The resistance of cell contaiing solution at the same temperature was found to be 55 ohms. The cell contant will be:A. `6.16cm^(-1)`B. `0.616cm^(-1)`C. `0.0616cm^(-1)`D. `616cm^(-1)`

Answer» Correct Answer - B


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