1.

The specific conductance of a saturated solution of a salt MX is2.8 xx 10^(-7) Omega^(-1) cm^(-1) and the equivalent conductances at infinite dilution of M^(+1) and X^(-1) ions are 68 and 72 Omega^(-1) cm2 / equivalent respectively Hence, the K_(sp) of MX is found to be

Answer»

`2 xx 10^(-6)`
`4 xx 10^(-12)`
`10^(-12)`
`4 xx 10^(-6)`

Solution :`^^= ^^_(M^(+)) + ^^_(X^(-)) = 68 + 72 , ^^_(M^(+)) = K xx (1000)/(5) (S=M+ " mole/L")`
`68 + 72 = (2.8 xx 10^(-7) xx 1000)/(S) , S = ( 2.8 xx 10^(-7) xx 1000)/(68 + 72) , S = 2 xx 10^(-6)`
`MX IMPLIES M^(+) + X^(-) , K_(SP) = [M^(+)][X^(-)], K_(sp) = (S)(S)`
` K_(SP) = S^(2) = (2 xx 10^(-6))^(2) = 4 xx 10^(-12)`


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