The specific conductance of a solution is 0.2 `ohm^(-1)" "cm^(-1)` and conductivity is 0.04 `ohm^(-1)`. The cell constant would beA. 1 `cm^(-1)`B. 0 `cm^(-1)`C. 5 `cm^(-1)`D. 0.2 `cm^(-1)`

The specific conductance of a solution is 0.2 `ohm^(-1)" "cm^(-1)` and

1.	The specific conductance of a solution is 0.2 `ohm^(-1)" "cm^(-1)` and conductivity is 0.04 `ohm^(-1)`. The cell constant would beA. 1 `cm^(-1)`B. 0 `cm^(-1)`C. 5 `cm^(-1)`D. 0.2 `cm^(-1)`
Answer» Correct Answer - C `K=Cxx`cell constant`=(K)/(C)=(0.2)/(0.04)=5cm^(-1)`.

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The specific conductance of a solution is 0.2 `ohm^(-1)" "cm^(-1)` and conductivity is 0.04 `ohm^(-1)`. The cell constant would beA. 1 `cm^(-1)`B. 0 `cm^(-1)`C. 5 `cm^(-1)`D. 0.2 `cm^(-1)`

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