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The specific conductance of saturated solution of AgCl is found to be `1.86xx10^(-6) ohm^(-1) cm^(-1)` and that of water is `6 xx 10^(-8) ohm^(-1) cm^(-1)`. The solubility of agCl is ... . Given, `Lambda_(AgCl)^(@)=137.2 ohm^(-1) cm^(2) eq^(-1)`A. `1.7xx10^(-3) M`B. `1.3xx10^(-5) M`C. `1.3xx10^(-4) M`D. `1.3xx10^(-6) M` |
Answer» Correct Answer - B `kappa_(AgCl)=kappa_(AgCl" (Solution)")-kappa_(H_(2)O)` `=1.86xx10^(-6)-6xx10^(-8)=1.8xx10^(-6) ohm^(-1) cm^(-1)` `Lambda_(AgCl)^(@)=kappaxx1000/S` `:. S=(kappaxx1000)/(Lambda_(AgCl)^(@))=(1.8xx10^(-6)xx1000)/137.2=1.31xx10^(-5) M` |
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