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The specific conductivity of a saturated solution of `Kl_(3)` is `4.59xx10^(-6)"ohm"^(-1)"cm"^(-1)` and its molar conductanc eis `"1.53 ohm"^(-1)"cm"^(2)"mol"^(-1)`. The `K_("sp")` of `Kl_(3)` will beA. `4xx10^(-12)`B. `27xx27xx10^(-9)`C. `9xx10^(-6)`D. `4xx10^(-4)` |
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Answer» Correct Answer - C `KI_(3) hArr K^(+)I_(3)^(-)` `K_("sp")=S^(2)` `lambda_(m)=(Kxx1000)/(S) rArr S=(4.59xx10^(-6)xx1000)/(1.53)` `S=3xx10^(-3),K_("sp")=9xx10^(-6)` |
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