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The specific heat c of a solid at low temperature shows temperature dependence according to the relation c = DT^(3)where D is a constant and T is the temperature in kelvin. A piece of this solid of mass m kg is taken and its terriperature is raised from 20 K to 30 K. The amount of heat required in the process in energy units |
| Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a> <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 10^(4) Dm`<br/>`(33//4) xx 10^(4) Dm`<br/>`(65//4) xx 10^(4) Dm`<br/>`(5//4) xx 10^(4) Dm`</p>Solution :The amount of heat supplied or gained by a body is directly proportional to mass ofbody and amount of change in temperature , i.e., `Delta Q = mc Delta T` <br/> Therefore , amount of heat supplied or gaind `Q = <a href="https://interviewquestions.tuteehub.com/tag/int-11513" style="font-weight:bold;" target="_blank" title="Click to know more about INT">INT</a> Delta Q = underset(T_(1)) <a href="https://interviewquestions.tuteehub.com/tag/overset-2905731" style="font-weight:bold;" target="_blank" title="Click to know more about OVERSET">OVERSET</a> (T_(2)) int mc Delta T ` <br/> Here, `c = DT^(3) , T_(1) = 20 K " and " T_(2) = 30 K` <br/> ` :. Q = underset(20)overset(30) int mDT^(3) dT = mD underset(20)overset(30) int T^(3) dT = mD [T^(4)/4]_(20)^(30)` <br/>` = (mD)/4 [(30)^(4) - (20)^(4)] = (mD)/4 xx 10^(4) [<a href="https://interviewquestions.tuteehub.com/tag/81-338942" style="font-weight:bold;" target="_blank" title="Click to know more about 81">81</a> - 16]` <br/> ` = (65/4) xx 10^(4) Dm`</body></html> | |