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The specific heats of a gas are measured as `C_p = (12.28 +-0.2)` units and C_(upsilon =(3.97 +- 03)` units. Find the value of gas constant R and percentage error in R. |
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Answer» Correct Answer - `(8.31 +- 0.5) units ; +- 6.016 %` Here, `C_p =(12.28 +- 0.2) units` `C_(upsilon) = (3.97 +- 0.3) units` `R = C_p - C_(upsilon)` `=(12.28 - 3.97) +- (0.2 + 0.3)` `=(8.31 +- 0.5 units` Percentage error in R `=(DeltaR)/(R )xx100 = ((Delta C_p +DeltaC_(upsilon))/(C_p - C_(upsilon)) xx100)` `=((0.2+0.3))/(8.31)xx100 = +-6.016%` |
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