InterviewSolution
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InterviewSolution
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The specific rotation of `alpha-`glucose is `+112^(@)` and `beta-`glucose is `+19^(@)` and the specific rotation of the constant equilibrium mixture is `+52.7^(@)`. Calculate the percentage composition of anomers `(alpha and beta)` in the equilibrium mixture. |
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Answer» Let `alpha-` and `beta`-glucos have `a` and `b%`, respectively. Equilibrium specific rotaion `=((axxsp.rot.of alpha)+(bxxsp.rot.of beta))/(100)` `+52.7=(axx112+bxx19)/(100)` `=(112a+(100-a)xx19)/(100)` Solving for `a` and `b: a=36.2%,b=63.8%` |
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