The speed of a Helium atom is equal to its root mean square speed at 27^@C. The approximate wavelength of this atom will be equal to :

The speed of a Helium atom is equal to its root mean square speed at 2

1.	The speed of a Helium atom is equal to its root mean square speed at 27^@C. The approximate wavelength of this atom will be equal to :
Answer» `1.37xx10^5` cm/sec `1.20 XX 10^(-39) `cm/sec `2.0xx10^(-39)` cm/sec `3.5xx10^(-39)` cm/sec Solution :`C = sqrt((3RT)/(M)` C `= lambda = H/(mv)` on SOLVING v = `1.37xx10^5 ` cm/sec