1.

The speed of a homogenous solid sphere after rolling down an inclined plane of vertical height h, from rest without sliding is

Answer»

`sqrt(gh)`
`sqrt(((g)/(5))gh)`
`sqrt(((4)/(3))gh)`
`sqrt(((10)/(7))gh)`

Solution :At BOTTOMMOST point, total kinetic will be mgh. Ratio of rotational to translational kinetic ENERGY will be 2/5
`:. K_(T)=(5)/(7)mgh=(1)/(2)mv^(2)`
`:.v=sqrt((10)/(7))gh`.


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