The speed of a train is reduced from 60km//h, to 15km//h, while it travels a distance of 450m. If the retardation is uniform, find how much further it will travel before coming to rest?

The speed of a train is reduced from 60km//h, to 15km//h, while it tra

1.	The speed of a train is reduced from 60km//h, to 15km//h, while it travels a distance of 450m. If the retardation is uniform, find how much further it will travel before coming to rest?
Answer» SOLUTION :Here `u=60xx(5)/(18)=(50)/(3)m//s` `v=15xx(5)/(18)=(25)/(6)m//s` Using `v^(2)=u^(2)+2as`, we GET `((50)/(3))^(2)=((25)/(6))^(2)+2xxaxx450or` `a=-(125)/(36xx12)m//s^(2)` If `s^(1)` is the further distance travelled before coming to rest, then `s^(1)=(v^(2))/(2a)=(25)/(6)xx(25xx36xx12)/(6xx2xx125)=30M`