1.

The speed of light is 3.0 x 108 ms-1. Calculate the distance covered by light in 2.00 ns.

Answer»

Speed of light = 3.0 x 108 ms-1

Time = 2.00 ns = 2 x 10-9 s

Distance travelled by light in 1 second

= 3.0 x 108 m

Distance travelled by light in 2 x 10-9 s

= 3.0 x 108 x 2 x 10-9 = 6 x 10-1 m

= 6.00 x 10-1 m = 0.600 m



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