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The speed time graph of a body of mass `300g` is shown in (fugure). Calculate the force actiong on the body. |
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Answer» Here, `m=300g= 0.3 kg` From the graph, acceleration of body `a=(dv)/(dt)= ((50-0))/((3-0))= 5/3m//s^(2)` `F= ma= 0.3xx5/3= 0.5N`. |
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