The speed with which a bullet can be fired is 150cm^(-1). Calculate the greatest distance to which it can be projected and also the maximum height to which it would rise.

The speed with which a bullet can be fired is 150cm^(-1). Calculate th

1.	The speed with which a bullet can be fired is 150cm^(-1). Calculate the greatest distance to which it can be projected and also the maximum height to which it would rise.
Answer» Solution :The GREATEST horizontal range is achieved at an angle of projectionn of `45^(@)` COMPONENTS of INITIAL velocity `=150cos45^(@)=106.06ms^(-1)` Now, if T is the time of FLIGHT, then considering the vertical motionof the bullet, `u=106.06 ms^(-1),a=-9.8ms^(-1),s=0,t=T` using `s=ut+1/2at^(2)` we get `0.106.06T-1/2 9.8T^(2)impliesT=(106.06xx2)/9.8=21.64` sec `:.` Maximum Horizontal range = horizontal component of velocity `xx` total time of flight. `=106.06xx21.64=2295.14m` Again if `H_("max")` be the maximum height of when the bullet rises, then `u=106.06ms^(-1),a=-9.8ms^(-1)` `v=0,s=H_("max")=(u^(2))/(2)impliesH_("max")=((106.06)^(2))/19.6=573.91m`