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The spin only magnetic moment of `Fe^(3+)` ion (inBM) is approximatelyA. 4B. 7C. 5D. 6 |
Answer» Correct Answer - D The electronic configuration of is `._(26)Fe=[Ar]3d^(6),4s^(2)` `Fe^(3+)=[Ar]3d^(5)` Thus , five unpaired electrons are present. :. Spin only magnetic moment, `mu=sqrt(n(n+2))BM` `n=5("unpaired electrons")` `mu=sqrt(5(5+2))BM=sqrt35=5.91~~6BM` |
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