1.

The spin only magnetic moment value (in Bohr magneton units) of Cr(CO)_(6)is

Answer»

0
2.84
4.9
5.92

Solution :Chromium in `Cr(CO)_(6)` is in zero OXIDATION state and has `[Ar]^(18)3d^(5)4s^(1)` as the ELECTRONIC CONFIGURATION. However, CO is a strong ligand, HENCE pairing up of electrons takes place leading to following configuration in `Cr(CO)_(6)`.

Since the complex has o unpaired electron, its magnetic moment is zero.


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