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The square root of `y^(2) + (1)/(y^(2)) + 2` isA. `y + (1)/(y)`B. `y - (1)/(y)`C. `y^(2) + (1)/(y^(2))`D. `y^(2) - (1)/(y^(2))` |
Answer» Correct Answer - A Use `a^(2) + b^(2) + 2ab = (a +b)^(2)` identity |
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