The stabiliy of nuclies has been explained in terms of binding energy. Higher is binding energy, more is stabliliy to nucleus. The binding energy is written as B.E = 931.478 xx Delta m' MeVm wehre Delta m' is mass decayed in amu. If B.E.//"nucleon" lies below the belt ofstablilty, the nucleus undergoes alpha- emission in order to lower down the energy level of nucleus but its n//p ratio increases. To lower down the energy level of nucleus but is n//p ratio increases.To lower downlevel of nucleus loses beta- particles and if stability is not gained, gamma- emission is noticed. A radioactive element on losing on alpha- particles shows a loss in its mass number by 4 units and atomic number by 2 units whereas beta- emission leads to a gain in at.no by one units and mass no. remains same. Loss in mass during the change.

The stabiliy of nuclies has been explained in terms of binding energy.

1.	The stabiliy of nuclies has been explained in terms of binding energy. Higher is binding energy, more is stabliliy to nucleus. The binding energy is written as B.E = 931.478 xx Delta m' MeVm wehre Delta m' is mass decayed in amu. If B.E.//"nucleon" lies below the belt ofstablilty, the nucleus undergoes alpha- emission in order to lower down the energy level of nucleus but its n//p ratio increases. To lower down the energy level of nucleus but is n//p ratio increases.To lower downlevel of nucleus loses beta- particles and if stability is not gained, gamma- emission is noticed. A radioactive element on losing on alpha- particles shows a loss in its mass number by 4 units and atomic number by 2 units whereas beta- emission leads to a gain in at.no by one units and mass no. remains same. Loss in mass during the change.
Answer» `3.07xx10^(-26)g` `3.07xx10^(-20)g` `1.86xx10^(-2)g` `1.86xx10^(-4)g` SOLUTION :1 amu `= 931.5 MEV` `:.` Mass decayed `= (17.25)/(931.5) = 0.0185` amu `= 0.0185xx1.66xx10^(-24)g` `= 3.07xx10^(-24)g`