1.

The standard e.m.f. of a cell involving one electron change is found to be 0.591V at 25^(@)C. The equilibrium constant of the reaction is (F = 96,500C mol^(-1) R = 8.314 J K^(-1) mol^(-1))

Answer»

`1.0 XX 10^(10)`
`1.0 xx 10^(5)`
`1.0 xx 10^(1)`
`1.0 xx 10^(30)`

Solution :`E_(CELL) = E_(cell)^(@) - (0.0591)/(N) LOGQ`
At equilibrium
`E_(cell) = 0, Q = K`
`0 = 0.591 - (0.0591)/(1) log K`
`log K = 10`
`K = 10^(10)`


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