1.

The standard e.m.f. of a cell, involving one electron change is found to be 0.591V at 25^(@)C. The equilibrium constant of the reaction is (F=96,500C" "mol^(-1),R=8.314KJ^(-1)" "mol^(-1))

Answer»

`1.0xx10^(10)`
`1.0xx10^(5)`
`1.0xx10^(1)`
`1.0xx10^(30)`

Solution :`E_(cell)=E_(cell)^(o)-(0.0591)/(n)logK_(C)`
At 298K `E_(cell)=0,0=0.591-(0.591)/(n)logK_(C)`
`logK_(C)=(0.591xx1)/(0.0591)=10,K_(c)="anti LOG 10"=1XX10^(10)`


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