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The standard e.m.f. of a cell involving one electron charge is found to be 0.591V at `25^(@)C` the equilibrium constant of the reaction is (F=96500C `"mol"^(-1)`:R=8.314 `JK^(-1)"mol"^(-1)`)A. `1.0xx10^(1)`B. `1.0xx10^(30)`C. `1.0xx10^(10)`D. `1.0xx10^(5)` |
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Answer» Correct Answer - C At 298 `E^(@)=(0.0591)/(n)"log" k_(c)` `0.591=(0.0591)/(1)"log"K_(c)` `"log" k_(c)=(0.5910)/(0.0591)` ` "log"k_(c)=10` `K_(c)=10^(10)` |
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