1.

The standard electrode potential for the half cell reactions are `Zn^(2+)+2e^(-)rarrZn ,E^(@)=-0.76V` `Fe^(2+)+2e^(-)rarrFe,E^(@)=-0.44V` The EMF of the cell reaction `Fe^(2+)+ZnrarrZn^(++)+Fe` isA. `-0.32V`B. `-1.20V`C. `+1.20V`D. `+0.32V`

Answer» Correct Answer - D
`Fe^(2+)+ZnrarrZn^(2+)+Fe`
`ZnrarrZn^(2+)+2e^(-)`
`ZnrarrZn^(2+)+2e^(-)`
`Fe^(2+)+2e^(-)rarrFe`
`Zn|Zn^(2+)||Fe^(2+)|Fe`
`EMF^(@)=E_(Fe^(2+)//Fe)^(@)-E_(Zn^(2+)//Zn)^(@)`
`=-0.44-(-0.76)`
`=0.76-0.44=+0.32V`


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