The standard emf of a galvanic cell involving cell reaction with n=2 found to be 0.295 V at `25^(@)C`. The equilibrium constant of the reaction would beA. `2xx10^(11)`B. `4xx10^(12)`C. `1xx10^(2)`D. `1xx10^(10)`

The standard emf of a galvanic cell involving cell reaction with n=2 f

1.	The standard emf of a galvanic cell involving cell reaction with n=2 found to be 0.295 V at `25^(@)C`. The equilibrium constant of the reaction would beA. `2xx10^(11)`B. `4xx10^(12)`C. `1xx10^(2)`D. `1xx10^(10)`
Answer» Correct Answer - D `E_(cell)^(o)=(2.303RT)/(nF)log" "K_(eq)` `0.295=(2.303xx8.314xx298)/(2xx96500)log" "K_(eq)` `log" "K_(eq)=(2xx96500)/(2.303xx3.314xx298)=10` `K_(eq)="antilog "10=1xx10^(10)`

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The standard emf of a galvanic cell involving cell reaction with n=2 found to be 0.295 V at `25^(@)C`. The equilibrium constant of the reaction would beA. `2xx10^(11)`B. `4xx10^(12)`C. `1xx10^(2)`D. `1xx10^(10)`

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