The standard `EMF` of a galvanic cell involving cell reaction with `n=2` is found to be `0.295 V` at `25^(@)C` . The equilibrium constant of the reaction would beA. `1 xx 10^(-10)`B. `29.5 xx 10^(-2)`C. `10`D. `1 xx 10^(10)`

The standard `EMF` of a galvanic cell involving cell reaction with `n=

1.	The standard `EMF` of a galvanic cell involving cell reaction with `n=2` is found to be `0.295 V` at `25^(@)C` . The equilibrium constant of the reaction would beA. `1 xx 10^(-10)`B. `29.5 xx 10^(-2)`C. `10`D. `1 xx 10^(10)`
Answer» Correct Answer - D `E_(cell)^(@) = (0.059)/(n)logK_(c)` `0.295 = (0.059)/(2)logK_(c)` `K_(c) = 1 xx 10^(10)`

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The standard `EMF` of a galvanic cell involving cell reaction with `n=2` is found to be `0.295 V` at `25^(@)C` . The equilibrium constant of the reaction would beA. `1 xx 10^(-10)`B. `29.5 xx 10^(-2)`C. `10`D. `1 xx 10^(10)`

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