1.

The standard emfof a galvaniccellinvolvingcellreactionwith n=2 is found to be 0.295 v at 25^(@)cthe equilibrium constantof thereactionwouldbe(Given F= 96500 C "mol"^(-1)m R =8 .314 "jk"^(-1) "mol"^(-1) )

Answer»

`2.0 xx10^(11)`
`4.0 xx10^(12)`
`1.0xx10^(2)`
`1.0 xx10^(10)`

Solution :By NERNST equation`E_(CELL) =E_(cell)^(@)-(2.303 RT)/(nF) log_(120) k`
At equilibriuim `E_(cell) =0`
Given that`R= 8.315 JK^(-1) mol^(-1)`
`therefore E_(Cell)^(@) =(0.0591)/(2) log_(10) K`
`because` Giventhat `E_(cell)^(@) =0.295 V`
`k=1xx10^(10)`


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