1.

The standard enthalpy of formation of Fe_(2)O_(3)(s) is - 824.2 kJ mol^(-1) . Calculate the enthalpychange for the reaction :4 Fe (s) + 3O_(2) (g) rarr 2Fe_(2) O_(3) (s)

Answer»


SOLUTION :`Delta_(r)H^(@) = [ 2 xx Delta_(F) H^(@) ( Fe_(2)O_(3))] - [ Delta_(f)H^(@) ( Fe)+ 3Delta_(f) H^(@) (O_(2))]`
`= [2(-824.2) ] -[0+0]`
`= - 1648.4kJ`


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