1.

The standard enthalpy of formation of H_(2(g)) and Cl_(2(g)) and HCl_((g)) are 218 kJ/mol and -92.31 kJ//mol respectively. Calculate standard enthalpy change in kJ for (1)/(2)H_(2(g))+(1)/(2)Cl_(2(g))rarrHCl_((g))

Answer»

`+431.99`
`-262.14`
`-431.99`
`+247.37`

Solution :`Delta_(r)H=DeltaH_("products")-DeltaH_("REACTANTS")`
`=-92.3-[(218)/(2)+(121.68)/(2)]=-92.3-[109+60.84]`
`=-262.14 kJ//mol`.


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