1.

The standard enthalpy of formation of hypothetical MgCl is -125kJ mol^(-1) and for MgCl_(2) is -642 kJ mol^(-1). What is the enthalpy of the disproportionation of MgCl ?

Answer»

`-492 KJ mol^(-1)`
`-392 kJ mol^(-1)`
`-767kJ mol^(-1)`
`-517 kJ mol^(-1)`

Solution :(i) `Mg_((s)) + Cl_(2(g)) RARR MgCl_(2(s)) , Detlta H_(1) = - 642`
(ii) `Mg_((s)) + 1//2Cl_(2(g)) rarr MgCl_((s)) , DELTA H_(2) = - 125`
(iii) `2MgCl rarr MgCl_(2) + Mg, Delta H`= ?
`Delta H = Delta H_(1)- Delta H_(2) = - 392 kJ mol^(-1)`


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