1.

The standard enthalpy of neutralization of strong acid and strong base is -57.3 kJ "equiv"^(-1). If the enthalpy of neutralization of the first proton of aqueous H_(2)S is -33.7 kJ mol^(-1) then the (pK_a)_(1) of H_(2)S is

Answer»

`((23.6 XX 10^(3) - T Delta s^@)/(2.303 RT))`
`((23.6 xx 10^(3) - T Delta s^@)/(2.303 RT))`
`((TDelta S^@ - 23.6)/(RT))`
`2.303((T DELTAS^(@) - 23.6)/(RT))`

ANSWER :A


Discussion

No Comment Found