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The standard enthalpy of neutralization of strong acid and strong base is -57.3 kJ "equiv"^(-1). If the enthalpy of neutralization of the first proton of aqueous H_(2)S is -33.7 kJ mol^(-1) then the (pK_a)_(1) of H_(2)S is |
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Answer» `((23.6 XX 10^(3) - T Delta s^@)/(2.303 RT))` |
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