1.

The standard free energy change, Delta G^(@) is related to equilibrium constant K_(p) as

Answer»

`K_(p) = - RT LN Delta G^(@)`
`K= ((e)/( RT))^(DeltaG^(@))`
`K_(p) = (DeltaG^(@))/( RT)`
`K_(p) = e^(- DeltaG^(@) //RT)`

Solution :`DeltaG^(@)= - RT lnK_(p) ` or `ln K_(p)=- DeltaG^(@) // RT ` or `K_(p) = e^(-DeltaG^(@) //RT )`


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