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The standard free energy change of the reaction `Cu^(2+)+Sn(s)rarrCu(s)+Sn^(2+)` Given : `E^(@)=0.48V`) is:A. `-31.8KJmol^(-1)`B. `-62.1KJmol^(-1)`C. `-79.2KJmol^(-1)`D. `92.64KJmol^(-1)` |
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Answer» Correct Answer - D `DeltaG^(@)=-nFE^(@)=-(2) 96500Cmol^(-1)(0.48V)=-92640J` `mol^(-1)=-92.64kJmol^(-1)` |
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