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The standard oxidation potential `E^@` for the half cell reaction are `Zn rarr Zn^(2+) + 2e^-` `E^@=+ 0.76 V ` `Fe rarr Fe^(2+) + 2e^-` `E^@=+ 0.41 V ` EMF of the cell rection is `Zn+Fe^(2+) rarr Zn^(2+)+Fe `A. `1.17 ` VB. `0.35` VC. `-1.17 V `D. `-0.35` V |
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Answer» Correct Answer - B Here oxidation potentials are given `E_(cell)^(@) = E_("OX (LHS)")^(@) - E_("OX (RHS)")^(@)` The cell is - Anode (LHS) `to` Higher SOP Cathode (RHS) `to` Lower SOP `E_(cell)^(@) = 0.76 - 0.41 = 0.35 V ` |
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